Hello Rupert, > On 06/13/2020 9:04 PM Rupert Boleyn <xxxxxx@gmail.com> wrote: > > > On 14Jun2020 0359, Thomas RUX wrote: > > None of the spreadsheets I downloaded for other fans or in MT have > > increased the fuel requirement needed by power plant based on the > > power required to operate the systems. > > > > I've done a quick check using CT Supplement 9 (S9) with the result > > that most of the hulls do not appear to increase the fuel load for the > > systems that consume EP. > > > > The Chrysanthemum Class DE on S9 p. 14 has a fuel load of 490 tons and > > the Power plant-9 has an output of 90 EP. Per CT LBB 5 HG 2e p. 27 one > > ton of fuel equals 1 EP of power plant output. The Power plant-9's > > output is 90 EP which means the power plant requires 90 tons of fuel > > to operate for four weeks. > > > > The Chrysanthemum has a J4 drive which requires 0.1 x 1,000 x 4 = 100 > > x 4 = 400 tons of fuel. > > > > The Computer Model/9-fib draws 12 EP, two fusion guns use 4 EP, and > > two PA turrets consume 10 EP. If these systems increase the fuel > > requirement then the total fuel load should be 490 + 26 = 512 tons. > > > > I've scoured CT LBB 5 HG 2e to find where the systems using EP require > > fuel in addition to the fuel required by the power plant. Could you > > please provide the source? > The numbers seem fine to me. 400 DTons of jump fuel, 90 DTons for a 90EP > power plant. 60EP goes to the manoeuvre drive (giving Agility-6), the > rest goes to the other systems. Thank you for confirming that my numbers are correct. My walk through of the Chrysanthemum was in reply to Postmark's comments on my first and second swings at building a CT LBB 5 HG 2e Express Boat. The first response is "Using book 5 you have room for a stateroom (4T) cargo (1T), Model 4 (4T + 2EP => 2T fuel + 4T PP) + Jump 4 (5T + 40T fuel + 8T PP + 4T PP fuel) + bridge (20T) That leaves 8T which would allow a 3G drive." In my second swing the Express Boat numbers after including a MD 3G left 6T allowing me to reinstall the second stateroom and bumping up cargo capacity from 1 to 3 tons. Postmark's response was "Unfortunately, you don't have 6T spare because the Model 4 needs 2 EP and at TL 13 costs you 6T." I admit that I missed the information Model 4 (4T + 2EP => 2T fuel + 4T PP). My understanding both from the trying to follow the design sequence and using fan created spreadsheets converted the EP requirements of the computer, weapons, and shields into fuel tonnage. To make sure that I was not out-to-lunch I ran several of the CT Supplement 7 designs through my spreadsheet to see if they followed Postmark's examples. The Chrysanthemum was the last hull I ran through and the one used to show my work. Again, thank you for confirming I appear to have followed the directions and finally did the math right. Tom Rux