If it's 5k away and 1k high, then the angle  of the top of the wall
from the observers point of view would be arcsin 0.2 or about 11.5
degrees
So it's above the 'horizon', but not that much.
It'd be real easy for objects between you can the Wall to block your view of it.

If you were out on a ocean, then you'd have a straight line of sight,
unless there's weather conditions.
And a sextant would be kinda handy for placing your distance from the wall.
I'd even imagine that with the reversed from a normal world curvature,
light houses on the shore of the ocean would be visible from a long
long way...and a sextant would suffice to get a distance there too.

On Thu, Jan 23, 2020 at 8:20 PM Greg Nokes <xxxxxx@nokes.name> wrote:
>
> A question:
>
> Given a ring world, how wide would it have to be so that an observer in the, say, middle 5000 miles of it would not see the shield walls?
>
> IIRC from Niven’s work, the walls are like 1000 miles tall, and the floor is flat, so curvature would not play. I don’t think there is an easy mathy way to solve this...
>
>
>
> Sent from my iPhone
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