Then the computer can just run that forward to determine thepositions when the players visit.Given that interplanetary travel is pretty much "point and shoot"with multi gee constant acceleration drives, all you need to do isfigure out the positions to get the distance, which won't changesignificantly during the trip.We do this thing from time to time (actually, our Traveller games don't resemble what you guys play at all, ours tend to be setups of situations where we attempt to nail a ship-to-ship railgun shot - which isn't easy and interplanetary flight is a typical thing too)Here's our good ship Hamiltonian, in orbit of Home which conveniently has no moon, is earthlike in mass, and has a system with a single gas giant in it (named Hot chi). Hamiltonian can accelerate at 9.81 m s^-2. The following plot is to scale and advances at 1 day every 8 seconds, presuming your browser's motion gif player respects playback at 24 fps:After 10 days in orbit (only the last day in stable orbit is plotted), Hamiltonian breaks orbit at 1g, line of sight for Hot chi. Home is in a fairly similar to earth orbit at about 1.05 AU semimajor axis, and this is hot chi:Eccentricity 0.0029896Semimajor Axis 1651939205556 meters(AU) 11.0425 astronomical unitsInclination 0. degreesLongitude of the Ascending Node 354.386 degreesArgument of Periapsis 3.22045 degreesTrue Anomaly 357.251 degreesDistance between Home and Hot chi at the start of the flight is 9.98456 AU. Time until turnover is 390208 seconds, and total flight time should be twice that (and characteristic energy at that point is a terrifying 7.3 * 10^12 J/kg - hyperbolic excess velocity 3.82 * 10^6 m/s - about 1% c).Pretty fast, however, we cannot ignore Hot chi's own velocity. In the 9 days, 46 minutes it takes to reach the point that Hot chi was at the start of flight, it has moved 0.0469 AU, or 550 Earth Diameters. As you mention, you can compute where Hot chi will be in 9 days (if you are in a predictable system), and that gets close enough (or your players just come to rest relative to their destination and then fly a second leg to their destination, but that doesn't seem as elegant).It doesn't work for railgun shots when your target is in orbit of a planet, though, and it's a relative of the same problem. You have distance to your target, compute flight time of the railgun shot, then compute where the target will be after the railgun shot flight time, which is a different distance and therefore a different flight time for the rail gun shot and so on. The problem is not hard if your target is not in orbit and your shot is not influenced by gravity, but I'm not really sure how to approach the problem in a closed form way for the situation that the target is in orbit.----- The Traveller Mailing List Archives at http://archives.simplelists.com/tml Report problems to xxxxxx@simplelists.com To unsubscribe from this list please go to http://www.simplelists.com/confirm.php?u= PltOdItWBSgOP4y0Q6abkGbDI1eus0 lz